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Q.

Escape velocity from the surface of the earth is v. The escape velocity from a planet whose mass and radius are twice those of the earth is

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a

v

b

16v

c

4v

d

2v

answer is A.

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Detailed Solution

V_{e} = \sqrt{\frac{2GM}{R}}

$M_{P} = 2 M, R_{P} = 2R$

$\sqrt{\frac{2GM}{R}} {=V}_{P} = V$

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Escape velocity from the surface of the earth is v. The escape velocity from a planet whose mass and radius are twice those of the earth is