Q.

Ethanol (C2H6O) and methanol (CH4O) form nearly ideal mixtures. A mixture consisting of 1.02 moles of ethanol and 0.98 moles of methanol has a total vapour pressure of 8.82 kPa at 293 K. When another 0.5 moles of methanol is added, the vapour pressure rose to 9.32 kPa. The vapour pressures of pure methanol and ethanol respectively (in bar) are

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a

0.128 and.0.226

b

0.226 and 0.118

c

0.064 and 0.113

d

0.113 and 0.064

answer is B.

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Detailed Solution

(A)
8.82=pCH3OH×0.982+pC2H5OH×1.022=0.49×pCH3OH+0.51pC2H5OH
(B)
9.32=pCH3OH×1.482.5+pC2H5OH×1.022.5=0.592×pCH3OH+0.408pC2H5OH
(C) On solving the two equations
pC2H5OH=6.41kPa=6.41kPa×0.01barkPa=0.064 bar pCH3OH=11.33kPa
or pCH3OH=11.33kPa×0.01barkPa=0.113 bar 

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