Ethanol is reacted with acidified ${\text{K}}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}$. What is the product formed?

${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}{\text{OH + K}}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}{\text{/H}}^{\text{+}}\to {\text{CH}}_{\text{3}}\text{CHO}\to {\text{CH}}_{\text{3}}\text{COOH}$

Ethanoic acid is produced by first oxidising ethanol to ethanal. Potassium dichromate is a potent oxidising agent, and when it reacts with ethanol, the orange-colored dichromate ion (IV) solution is transformed into a green Cr(III) ion solution. This reaction is used to identify alcohol in suspected inebriated drivers' breath.

Therefore, the correct option is option (B) ${\text{CH}}_{\text{3}}\text{COOH}$