Ethanol when reacts with PCl5 gives A, POCI3 and HCl. A reacts with dry Ag2O to form B(major product) and AgCl. A and B respectively are :

C2H5Cl and C2H5OC2H5Concept: This question involves two steps:Step 1: Reaction of ethanol (C2H5OH) with phosphorus pentachloride (PCl5):C2H5OH + PCl5 → C2H5Cl + POCl3 + HClThe product A is ethyl chloride (C2H5Cl).Step 2: Reaction of ethyl chloride (C2H5Cl) with dry silver oxide (Ag2O):C2H5Cl + Ag2O → C2H5OC2H5 + AgClDry silver oxide acts as a reagent that replaces the halogen atom (Cl) with an ethoxy group (-OC2H5), resulting in the formation of diethyl ether (C2H5OC2H5) as compound B.Compound A is ethyl chloride (C2H5Cl), and compound B is diethyl ether (C2H5OC2H5).The correct option is a. C2H5Cl and C2H5OC2H5.

Ethanol when reacts with PCl5 gives A, POCI3 and HCl. A reacts with dry Ag2O to form B(major product) and AgCl. A and B respectively are :

C2H5Cl and C2H5OC2H5Concept: This question involves two steps:Step 1: Reaction of ethanol (C2H5OH) with phosphorus pentachloride (PCl5):C2H5OH + PCl5 → C2H5Cl + POCl3 + HClThe product A is ethyl chloride (C2H5Cl).Step 2: Reaction of ethyl chloride (C2H5Cl) with dry silver oxide (Ag2O):C2H5Cl + Ag2O → C2H5OC2H5 + AgClDry silver oxide acts as a reagent that replaces the halogen atom (Cl) with an ethoxy group (-OC2H5), resulting in the formation of diethyl ether (C2H5OC2H5) as compound B.Compound A is ethyl chloride (C2H5Cl), and compound B is diethyl ether (C2H5OC2H5).The correct option is a. C2H5Cl and C2H5OC2H5.

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Ethanol when reacts with PCl₅ gives A, POCI₃ and HCl. A reacts with dry Ag₂O to form B(major product) and AgCl. A and B respectively are :

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$C_{2} H_{5} Cl and C_{2} H_{5} {OC}_{2} H_{5}$

$C_{2} H_{4} and C_{2} H_{5} {OC}_{2} H_{5}$

$C_{2} H_{6} and C_{2} H_{5} {OC}_{2} H_{5}$

$C_{2} H_{6} and C_{2} H_{5} {NO}_{2}$

answer is A.

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Detailed Solution

C₂H₅Cl and C₂H₅OC₂H₅

Concept: This question involves two steps:

Step 1: Reaction of ethanol (C₂H₅OH) with phosphorus pentachloride (PCl₅):

C₂H₅OH + PCl₅ → C₂H₅Cl + POCl₃ + HCl

The product A is ethyl chloride (C₂H₅Cl).

Step 2: Reaction of ethyl chloride (C₂H₅Cl) with dry silver oxide (Ag₂O):

C₂H₅Cl + Ag₂O → C₂H₅OC₂H₅ + AgCl

Dry silver oxide acts as a reagent that replaces the halogen atom (Cl) with an ethoxy group (-OC₂H₅), resulting in the formation of diethyl ether (C₂H₅OC₂H₅) as compound B.

Compound A is ethyl chloride (C₂H₅Cl), and compound B is diethyl ether (C₂H₅OC₂H₅).

The correct option is a. C₂H₅Cl and C₂H₅OC₂H₅.