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Q.

Ethene gives with acidic ${KMnO}_{4}$ solution

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a

Acetaldehyde

b

Ethylene oxide

c

Formaldehyde

d

Ethylene glycol

answer is C.

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Detailed Solution

${CH}_{2} = {CH}_{2} + 2 [O] \to_{}^{{KMnO}_{4}} \underset{Formaldehyde}{HCHO + HCHO} .$

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Ethene gives with acidic KMnO4 solution