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Ethoxyethene is written as follows,
$H_{2} C = CH - O - {CH}_{2} - {CH}_{3}$ .
The structure of 2-Chloro-1-ethoxyethene (incorrect name) with correct numbering will be

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$H_{2} C = CH - O - \overset{1}{C} H_{2} - \overset{2}{C} H_{2} - Cl$

$Cl - \overset{1}{C} H = \overset{2}{C} H - O - {CH}_{2} - {CH}_{3}$

answer is D.

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Detailed Solution

2-Chloro- I -ethoxyethene

$Cl - \overset{1}{CH} = \overset{2}{CH} - O - {CH}_{2} - {CH}_{3}$

correct name 1-Chloro-2-ethoxyethene.

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