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Ethyl acetate reacts with _{$C H_{3} M g B r$} to form

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Primary alcohol and an acid

Secondary alcohol

Tertiary alcohol

An acid

answer is B.

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Detailed Solution

Esters react with Grignard reagent to form _{$t e r t$} -alcohols having at least two alkyl groups, introduced through Grignard reagent, identical, the third introduced through ester may be similar or different.

_{$C H_{3} C O O C_{2} H_{5} + C H_{3} M g l \overset{H_{2} O}{\to} C H_{3} C O C H_{3}$}

_{$\to_{(i i) H_{2} O}^{(i) C H_{3} M g l} C H_{3} - \overset{\overset{C H_{2} C H_{3}}{|}}{\underset{\underset{O H}{|}}{C}} - C H_{3}$}

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