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Q.

Ethyl alcohol reacts with thionyl chloride in the presence of pyridine to give

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a

${CH}_{3} {CH}_{2} Cl + H_{2} O + {SO}_{2}$

b

${CH}_{3} {CH}_{2} Cl + {SO}_{2} + {Cl}_{2}$

c

${CH}_{3} {CH}_{2} Cl + HCl$

d

${CH}_{3} {CH}_{2} Cl + HCl + {SO}_{2}$

answer is C.

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Detailed Solution

Ethyl alcohol forms ethyl chloride with thionyl chloride in presence of pyridine.

${CH}_{3} {CH}_{2} OH + {SOCl}_{2} \overset{Pyridine}{\to} {CH}_{3} {CH}_{2} Cl + {SO}_{2} + HCl$

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