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Q.

Ethyl bromide on treatment with alcoholic KOH gives

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a

Acetic acid

b

Ethylene 

c

Ethane

d

Ethanol 

answer is A.

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Detailed Solution

  • CH3CH2Br + KOH →CH2=CH2 +KBr +H2O 

The above reaction explain the formation of ethylene when ethyl bromide on treatment with alcoholic KOH. 

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