Ethyl iodide and n-propyl iodide are allowed to undergo Wurtz reaction. The alkane which will not be obtained in this reaction is

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octane

Pentane

Hexane

Butane

answer is C.

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Detailed Solution

$C_{2} H_{5} - I + C H_{3} - C H_{2} - C H_{2} - I \to_{e t h e r}^{N a} C_{4} H_{10} +$ $C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{3} + C_{6} H_{14}$

Observe the reaction, Now in the mechanistic pathway the intermediates are Ethyl free radical and n-propyl free radical. can give Butane,pentane and hexane only.

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