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Ethylene glycol gives oxalic acid on oxidation with

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Periodic acid

Acidified $K_{2} {Cr}_{2} O_{7}$

Alkaline ${KMnO}_{4}$

Acidified ${KMnO}_{4}$

answer is A.

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Detailed Solution

Oxalic acid is formed by oxidation of ethylene glycol with acidified potassium dichromate.

$l_{\overset{{CH}_{2} OH}{Ethylene glycol}}^{{CH}_{2} OH} + 4 [O] \to_{H_{2} {SO}_{4}}^{K_{2} {Cr}_{2} O_{7}} l_{\underset{Oxalic acid}{COOH}}^{COOH} + 2 H_{2} O$

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