Ethylene is produced by cyclobutene …. according to the reaction :
$C_{4} H_{8} \overset{Δ}{⟶} 2 C_{2} H_{4}$ The rate constant is $2.48 x 10^{- 4} \sec^{- 1}$ . In what time will the molar ratio of the ethylene to cyclobutene in reaction mixture attain the value 1?

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25 minute

27.25 minute

28.25 minute

20 minute

answer is A.

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Detailed Solution

the molar ratio of the ethylene to cyclobutene in reaction mixture attain the value 1

$\begin{array}{l} \underset{a - x}{A} \to \frac{2 B}{2 x} \\ \frac{2 x}{a - x} = 1 \\ \Rightarrow x = \frac{a}{3} \\ 2.48 \times 10^{- 4} \times t = \ln (\frac{a}{\frac{2 a}{3}}) \\ \Rightarrow t = 27.25 \min . \end{array}$

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