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Ethylene reacts with HBr forming ‘X’ which on reaction with moist ${Ag}_{2} O$ gives ‘Y’. When ‘Y’ is heated with alumina at 350⁰C compound Z is formed. Then X and Z are

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Bromo ethane, ethanol

Ethanol, ethoxy ethane

Ethyl bromide, diethyl ether

Bromo ethane, Ethene

answer is D.

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Detailed Solution

$H_{2} C = C H_{2} + H B r \to C_{2} H_{5} B r$ $\overset{A g_{2} O}{\to} C_{2} H_{5} O C_{2} H_{5} \to_{35 0^{0} C}^{A l_{2} O_{3}} C_{2} H_{4}$

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