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Q.

Ethylidene chloride can be prepared by the reaction of HCl and

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a

Acetylene

b

Ethylene glycol

c

Ethane

d

Ethylene

answer is C.

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Detailed Solution

$\begin{aligned} CH \equiv CH \overset{HCl}{\to} {CH}_{2} = CHCl \\ \overset{HCl}{\to} {CH}_{3} - {CHCl}_{2} \end{aligned}$

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