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Q.

Evaluate : cos 6 θ + sin 6 θ

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a

1 -  sin 2 θ ∙ cos 2 θ

b

1 - 3sin2θ.cos2θ

c

1 - 3 sin 2 θ 

d

1 - 7 sin 2 θ ∙ co2 2 θ

answer is B.

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Detailed Solution

cos 6 θ + sin 6 θ = (cos2θ)3 + (sin2θ)3

                      = (cos 2 θ + sin 2 θ)(cos 4 θ - cos 2 θ ∙ sin 2 θ + sin 4 θ)

                      = 1 ∙ {cos 4θ+ sin 4 θ - cos 2 θ ∙ sin 2 θ}

                      = 1 ∙ {(cos2θ+sin2θ)2 - 2 cos 2 θ ∙ sin 2 θ - cos 2 θ ∙ sin 2 θ}

                      = 1 ∙ {(cos2θ+sin2θ)2 - 3 cos2 2 θ ∙ sin2 2 θ}

                   = 1 - 3 cos2 2 θ ∙ sin2 2 θ

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