Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Evaluate $39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)$ by factorising first.

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

3y(5y-7)

y(5y+7)

3y(5y+7)

y(5y-7)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given expression:

39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)

.
Take 2 common from brackets in the numerator and also factorise 39y³ and simplify.

39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)

= 39 y 3 50 y 2 − 98 26 y 2 (5 y + 7)

= 13 y 2 × 3 y × 2 25 y 2 − 49 26 y 2 (5 y + 7)

= 26 y 2 × 3 y 25 y 2 − 49 26 y 2 (5 y + 7)

Cancel 26y² from numerator and denominator.

39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)

3 y 25 y 2 − 49 (5 y + 7)

Rewrite terms in bracket in numerator in from of square.

39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)

3 y (5 y) 2 − 72 (5 y + 7)

Apply identity

x + y x − y = x 2 − y 2

39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)

= 3 y (5 y + 7) (5 y − 7) (5 y + 7)

Cancel common factor (5y+7) from numerator and denominator.

39 y 3 50 y 2 − 98 ÷ 26 y 2 (5 y + 7)

=3y(5y-7).
Hence, option 1 is correct.

Watch 3-min video & get full concept clarity