Evaluate each of the following: 

(a) $(–30)÷10$ 

(b) $50÷(–5)$ 

(c) $(–36)÷(–9)$ 

(d) $(-49)÷\left(49\right)$ 

(e) $13÷\left[(–2) + 1\right]$ 

(f) $0÷(-12)$ 

(g) $(-31)÷\left[(–30) + (–1)\right]$ 

(h) $\left[(–36) ÷ 12\right]÷3$ 

(i) $\left[(– 6) + 5)\right]÷\left[(–2) + 1\right]$

(a) Consider the given expression $(–30)÷10$.

Perform division  and cancel out the common terms to get the following,

$(–30)÷10=\frac{-30}{10}=-3$

Hence, the evaluation of the given expression is $-3$.

(b) Consider the given expression $50÷(–5)$.

Perform division  and cancel out the common terms to get the following,

$\left(50\right)÷\left(-5\right)=\frac{50}{-5}=-10$

Hence, the evaluation of the given expression is $-10$.

(c) Consider the given expression $(–36)÷(–9)$.

Perform division  and cancel out the common terms to get the following,

$(-36)÷\left(-9\right)=\frac{-36}{-9}=4$

Hence, the evaluation of the given expression is $4$.

(d) Consider the given expression $(-49)÷\left(49\right)$.

Perform division  and cancel out the common terms to get the following,

$(-49)÷\left(49\right)=\frac{-49}{49}=-1$

Hence, the evaluation of the given expression is $-1$.

(e) Consider the given expression $13÷\left[(–2) + 1\right]$.

Perform division  and cancel out the common terms to get the following,

$13÷\left[\left(-2\right)+1\right]=\frac{13}{\left[\left(-2\right)+1\right]}=\frac{13}{-1}=-13$

Hence, the evaluation of the given expression is $-13$.

(f) Consider the given expression $0÷(-12)$.

Perform division  and cancel out the common terms to get the following,

$0÷\left(-12\right)=\frac{0}{\left(-12\right)}=0$

Hence, the evaluation of the given expression is $0$.

(g) Consider the given expression $(-31)÷\left[(–30) + (–1)\right]$.

Perform division  and cancel out the common terms to get the following,

$(-31)÷\left[(–30) + (–1)\right]=\frac{-31}{\left[(–30) + (–1)\right]}=\frac{-31}{-31}=1$

Hence, the evaluation of the given expression is $1$.

(h) Consider the given expression $\left[(–36) ÷ 12\right]÷3$.

Perform division  and cancel out the common terms to get the following,

$\left[(–36) ÷ 12\right]÷3=\frac{\left[(–36) ÷ 12\right]}{3}=\frac{-36}{12\times 3}=-1$

Hence, the evaluation of the given expression is $-1$.

(i) Consider the given expression $\left[(– 6) + 5)\right]÷\left[(–2) + 1\right]$.

Perform division  and cancel out the common terms to get the following,

$\left[(– 6) + 5)\right]÷\left[(–2) + 1\right]=\frac{\left[(– 6) + 5)\right]}{\left[(–2) + 1\right]}=\frac{-1}{-1}=1$

Hence, the evaluation of the given expression is $1$.