Q.

Evaluate I=xsin-1(x2)1-x4dx

OR

Evaluate x+1x(1-2x)dx

 

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answer is 1.

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Detailed Solution

Let I=xsin-1(x2)1-x4dx Put sin-1(x2)=t 11-x4(2x)dx=dtx1-x4dx=12dt I=t2dt=12t dt  =12t22+C         xn dx=xn+1n+1  =14t2+C   =14(sin-1x2)2+C 

OR

Let I=x+1x(1-2x)dx Let x+1x(1-2x)=Ax+B1-2x x+1=A(1-2x)+Bx Putting x=0 in Eq. (i), we get            1=AA=1 Putting x=12in Eq. (i), we get             32=12BB=3 x+1x(1-2x)=1x+31-2x            I=x+1x(1-2x)dx=1x+31-2xdx                  =1xdx+311-2xdx                  =1xdx-32-21-2xdx                  =logx-32log1-2x+C

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