EW of Sulphur in its reaction with conc.HNO₃ is

${\stackrel{0}{\mathrm{S}}}_8+48{\mathrm{HNO}}_3→8{\mathrm{H}}_2\stackrel{+6}{\mathrm{S}}{\mathrm{O}}_4+48{\mathrm{NO}}_2+16{\mathrm{H}}_2\mathrm{O}$

Increase in Ox.state / atom of 'S' = 6

$\mathrm{EW} \mathrm{of} \text{'}\mathrm{S}\text{'} =\frac{\mathrm{AW}}{6}=\frac{32}{6}$

 Increase in Ox. state / molecule of sulphur = 48

$\mathrm{EW} \mathrm{of} \text{'}\mathrm{S}\text{'} =\frac{\mathrm{MW}}{48}=\frac{256}{48}$