Example showing ionisation isomerism

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$[Co ({NO}_{3}) {({NH}_{3})}_{5}] {SO}_{4} & [Co ({SO}_{4}) {({NH}_{3})}_{5}] {NO}_{3}$

$[Co {({NH}_{3})}_{4} {Cl}_{2}] Cl & [Co {({NH}_{3})}_{5} Cl] {Cl}_{2}$

$[Cr {(H_{2} O)}_{5} Cl] {Cl}_{2} \cdot H_{2} O & [Cr {(H_{2} O)}_{4} Cl l_{2}] Cl \cdot 2 H_{2} O$

$[Pt {({NH}_{3})}_{4}] [PtCl l_{4}] & {[Pt {({NH}_{3})}_{3} Cl]}_{2} [PtCl l_{4}]$

answer is A.

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Detailed Solution

Ionization isomers are similar, with the exception that a ligand has switched places with an anion or neutral molecule that was once outside the coordination complex. The other ligands and the core ion are the same. An octahedral isomer, for instance, will contain five ligands that are the same but a different sixth ligand.

Hence, the correct option is - Option (A) $[Co ({NO}_{3}) {({NH}_{3})}_{5}] {SO}_{4} & [Co ({SO}_{4}) {({NH}_{3})}_{5}] {NO}_{3}$