Excess of ozone when passed through 1 lit of 1M H2O2 solution, the volume of oxygen liberated at STP will be.......

1 mole --------------------2 x 22.4 = 44.8 lit volume of O2 liberated at STP when excen of O3 is passed though 1lit of 1M H2O2 solution is 44.8 lit.

Excess of ozone when passed through 1 lit of 1M H2O2 solution, the volume of oxygen liberated at STP will be.......

1 mole --------------------2 x 22.4 = 44.8 lit volume of O2 liberated at STP when excen of O3 is passed though 1lit of 1M H2O2 solution is 44.8 lit.

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Excess of ozone when passed through 1 lit of 1M H₂O₂ solution, the volume of oxygen liberated at STP will be.......

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11.2 lit

22.4 lit

5.6 lit

44.8 lit

answer is D.

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Detailed Solution

$large mathop {{H_2}{O_2}}limits_{1mole} + {rm{ }}{O_3};{rm{ }} to {rm{ }}{H_2}O; + ;mathop {2{O_2}}limits_{2mole}$
$large \\M =frac{eta }{V lit}\\eta;=;Mtimes;V(lit)\\eta;=;1times 1\\eta;=;1mole$
1 mole --------------------2 x 22.4
= 44.8 lit
$large therefore$ volume of O₂ liberated at STP when excen of O₃ is passed though 1lit of 1M H₂O₂ solution is 44.8 lit.