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Q.

Excitation energy of hydrogen atom is 13.6eV. Match the following:

 COLUM N-I COLUM N-II
A)Energy of second excited state of hydrogenP)-3.4eV
B)Energy of fourth state of He+Q)-108.9eV
C)Energy of first excited state of Li2+R)-1.5eV
D)Energy absorbed when the electron in Li2+ makes transition from 3rd to 1st orbitS)-30.6eV

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a

A-R, B-P, C-S, D-Q

b

A-P, B-Q, C-S, D-R

c

A-R, B-Q, C-P, D-S

d

A-S, B-Q, C-R, D-P

answer is B.

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Detailed Solution

The energy of an electron in a orbit of a hydrogen like ion will be given by E=13.6n2z2

Energy of second excited state of hydrogen = E=13.63212=-1.5eV

Energy of fourth state of He+=E=13.65222=-3.4eV

Energy absorbed when the electron in Li2+ makes transition from 3rd to 1st orbit E=-112-132×13.6×32=-108.8eV

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