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Q.

Explain Calvin cycle.

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Detailed Solution

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  • Calvin cycle explains about CO2 fixation in photosynthesis. It is worked out by Calvin and his co-workers.
  • It is present in both C3 plants and C4 plants.
  • It occurs in 3 stages.
    • i) Carboxylation 
    • ii) Reduction
    • iii) Regenaration

i) Carboxylation: 6RUBP molecules accept 6CO2 molecules and converting into 12 molecules of 3- PGA (Phosphoglyceric acid) in presence of RuBisco6RUBP + 6 CO2 + H2O RUBISCO12, 3 - PGA

ii) Reduction: This occurs in two steps. 

  • In first step 12PGA taking 12 ATP and converting 12 molecules of 1,3 bis PGA (Phosphoglyceric acid) in presence of phosphoglycerokinase.
    • 12 molecules of PGA + 12 ATP Kinase12 molecules of 1,3 bis PGA + 12 ADP
  • In 2nd step 12 mol of 1,3 bis phosphoglyceric acid is reduced into12 molecules of G3P.
    • 12PGA + 12NADPH + H+ Dehydrogenase12G - 3 - P + 12 NADP+ + 12 H2PO4-

iii) Regeneration: 2 molecules of G-3p used to synthesise hexose in cytoplasam. So
10 G-3-P are used for RUBP regeneration.

  • 4 molecules of - G - 3 - P Isomerase 4 DHAP(dihydroxy acetone phosphate)
  • 2 molecules of - G - 3 - P + 2 molecules of DHAP Aldolase2 Fructose,1,6 bis phosphate
  • 2 mol of Fructose -1,6 - bis phosphate Phosphatase2 mol of Fructose 6 phosphate 2Pi
  • 2 mol of Fructose - 6phosphate + 2 G - 3 - P Transketolase2mol of Xylulose - 5 - phosphate + 2 mol Erythrose - 4 - Phosphate.
  • 2 E - 4 - p + 2 DHAP Aldolase2 mol of sedoheptulose - 1,7 - bisphosphate
  • 2 mol of Sedoheptulose - 1,7 - bis phosphate phosphatase2 mol of Sedoheptulose - 7 - phosphate + 2 mol G - 3 - P Transketolase2 mol of Xyluose - 5 - P + 2 mol of Ribose - 5 - Phosphate
  • 4 mol of xylusose - 5 - p epimerase4 mol of Ribulose - 5 - P
  • 2mol of Ribose - 5 - p isomerase2 mol of Ribulose - 5 - P
  • 6mol of Ribulose - 5 - p + 6 ATP kinase6 mol of Ribulose 1, - 5 - P + 6 ADP

Note : 6 times of cycle gives 1 glucose molecule. 18 ATP, 12 NADPH required for 6CO2 molecule
fixation.

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