Explain the structures of
a) XeF₆
b) XeOF₄

Structure of XeF₆:

1. Hybridization: Xenon in XeF₆ undergoes sp³d³ hybridization, utilizing its valence electrons to form six bonds with fluorine atoms and retaining one lone pair, resulting in a total of seven electron pairs.
2. Geometry: The presence of six bonding pairs and one lone pair leads to a distorted octahedral shape, often described as a monocapped octahedron.
3. Bonding Details: Each Xe–F bond involves the sharing of electrons between xenon and fluorine atoms, with the lone pair causing slight distortions from the ideal octahedral geometry.
4. Physical Properties: XeF₆ is a colorless solid that sublimates into intensely yellow vapors.

Structure of XeOF₄:

• Hybridization: In XeOF₄, xenon undergoes sp³d² hybridization, forming bonds with one oxygen atom and four fluorine atoms, and possessing one lone pair, totaling six electron pairs.
• Geometry: The molecular geometry is square pyramidal, with the oxygen atom occupying an axial position and the four fluorine atoms forming the base of the pyramid.
• Bonding Details: The Xe=O bond is a double bond, while each Xe–F bond is a single bond. The lone pair on xenon influences the square pyramidal shape by occupying an equatorial position, leading to slight distortions.
• Physical Properties: XeOF₄ is an unstable colorless liquid with a melting point of −46.2°C.