Express "9504" as a product of prime factors

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$2^{2} \times 3^{4} \times 5^{1}$

$2^{3} \times 3^{2} \times 7^{6}$

$3^{2} \times 7^{2} \times 11^{2}$

$2^{5} \times 3^{3} \times 11^{1}$

answer is D.

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Detailed Solution

${\begin{array}{l} \begin{matrix} 2 & 9504 \\ 2 & 4752 \\ 2 & 2376 \\ 2 & 1188 \\ 2 & 594 \\ 3 & 297 \\ 3 & 99 \\ 3 & 33 \\ 11 \end{matrix} \\ 9504 = 2^{5} \times 3^{3} \times 11 \\ H e n c e o p t i o n (D) f o l l o w s \end{array}}^{}$

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