Expression for hydrolysis constant (K_h) for the hydrolysis of ${NH}_{4} Cl$ salt is

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$K_{h} = \frac{K_{w}}{K_{b}}$

$K_{h} = \frac{K_{w}}{K_{a}}$

$K_{h} = \frac{K_{w}}{K_{a} . K_{b}}$

$K_{h} = \frac{K_{a}}{K_{w}}$

answer is A.

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Detailed Solution

The strong acid and weak base salt reacting with water, which is the reverse process of the neutralization reaction is known as hydrolysis. The cation NH₄⁺of the salt is the conjugate acid or a weak base (ammonium hydroxide).

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