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$E_{Z n^{2 +} / Z n}^{0} = - 0.76 V; E_{C u^{2 +} / C u}^{0} = + 0.34 V$ Change in standard free energy for $Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$ is

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-106.2 kJ

-180.9 kJ

-342.6 kJ

-212.4 kJ

answer is D.

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Detailed Solution

$E_{c e l l}^{0} = + 0.34 - (- 0.76) = 1.1 V$
$Δ_{}^{0} G = - 2 (96.5) (1.1) = - 212.4 k J$

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