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Q.

f:NA and g:NB are two onto functions such that f(n)=[nsec2θ]  and g(n)=[ncosec2θ], for some θ and nN where N is set of natural numbers, if sec2θ is irrational, (where[.] denotes the greatest integer function) then which of following is/are true 

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a

AB=ϕ

b

AB=N

c

f and g are bijective functions

d

AB is non-empty finite set

answer is A, B, C.

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Detailed Solution

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Since sec2θ>1[(n+1)sec2θ]>[nsec2θ] Hence, f and g are both one-one

Let  k<nsec2θ<k+1 and k<mcosec2θ<k+1

kcos2θ<n<(k+1)cos2θ and ksin2θ<m<(k+1)sin2θ

Adding given k< integer <k+1AB=ϕ

Suppose kAnsec2θ<k and (k+1)<(n+1)sec2θ

n<kcos2θ and n+1>(k+1)cos2θk<(kn)cosec2θ,k+1>(kn)cosec2θ

 [(kn)cosec2θ]=kB

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