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$f : R \to R, g : R \to R$ defined by $f (x) = 2 x + 1, g (x) = x^{2} + 1$ then arrange the following is ascending order
a) $f o g (2)$ b) $g o f (3)$ c) $g o f (- 1)$ d) $f o g (- 1)$

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$d, a, b, c$

$a, b, c, d$

$d, a, c, b$

$c, d, a, b$

answer is B.

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Detailed Solution

$f o g (x) = f (g (x)) = f (x^{2} + 1) = 2 x^{2} + 3$

$g o f (x) = g (f (x)) = g (2 x + 1) = 4 x^{2} + 4 x + 2$

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