f(x)=x−1+(x+24)−10x−1,1<x<26 be real valued function, then f'(x) for 1<x<26 is

f(x)=x−1+|x−1−5|f(x)=5,1<x<26f'(x)=0

f(x)=x−1+(x+24)−10x−1,1<x<26 be real valued function, then f'(x) for 1<x<26 is

f(x)=x−1+|x−1−5|f(x)=5,1<x<26f'(x)=0

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$f (x) = \sqrt{x - 1} + \sqrt{(x + 24) - 10 \sqrt{x - 1}}, 1 < x < 26$ be real valued function, then $f' (x)$ for $1 < x < 26$ is

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$2 \sqrt{x - 1}$

$\frac{1}{\sqrt{x - 1}}$

$5$

$0$

answer is D.

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$f (x) = \sqrt{x - 1} + | \sqrt{x - 1} - 5 |$

$f (x) = 5, 1 < x < 26$

$f' (x) = 0$

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f(x)=x−1+(x+24)−10x−1,1<x<26 be real valued function, then f'(x) for 1<x<26 is

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$f (x) = \sqrt{x - 1} + \sqrt{(x + 24) - 10 \sqrt{x - 1}}, 1 < x < 26$ be real valued function, then $f' (x)$ for $1 < x < 26$ is