Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Factorise 7429 into its prime factors using Factor tree approach.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

13 x 17 x 19

b

13 x 29 x 4

c

23 x 31 x 7

d

17 x 19 x 23

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

17 x 19 x 23

Question Image

1. We first check if 7429 is divisible by 2. Since it is an odd number, it is not divisible by 2. Next, we try the smallest odd prime numbers.

2. Dividing 7429 by 17 gives a quotient of 437, which means 7429 is divisible by 17. Therefore, one of the prime factors is 17.

3. Now, we factorize 437. Dividing 437 by 19 results in a quotient of 23, indicating that 437 is divisible by 19. Thus, another prime factor is 19.

4. Finally, 23 is already a prime number. Therefore, the last prime factor is 23.

So, the prime factorization of 7429 can be expressed as:

7429 = 17 × 19 × 23

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring