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Factorise the given expression 4x²+4x+1, using the identity a²+ 2ab + b²= (a+b)².

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(2x-1)²

(2x+2)²

(2x-2)²

(2x+1)²

answer is D.

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Detailed Solution

$4 x^{2} + 4 x + 1 = {(2 x)}^{2} + 2 (2 x) (1) + {(1)}^{2}$

Compared to the identity ${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ , where

$a = 2 x$ and $b = 1$

Therefore, $4 x^{2} + 4 x + 1 = {(2 x + 1)}^{2}$

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