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Q.

Factorization of x2+76x+60 will be ____.


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Detailed Solution

We are given the equation x2+76x+60 ..............… (1)
Since we know general form of a quadratic equation is ax2+bx+c=0
On comparing equation (1) with general equation we can write a=1, b=76, c=60
Now we calculate the product of coefficient of x2 and the constant term
Since coefficient of x2 is 1 and the constant term is 60
Then the value of product is 60×1 = 60............… (2)
We have to break the coefficient of ‘x’ i.e. 76
 in such a way that the sum of those terms give 76  and the product of those terms gives 60.
We write prime factorization of the number 60
⇒ 60 = 2×2×3×5
So we can form 60 = 5×2×6, but here we are dealing with under root of 6, so we will take both the terms as multiples of  6 so that on multiplication they give an answer 6.
We can write  76= 56+26
Substitute the value of  76= 56+26  in equation (1)
⇒ x2+76 x+60 = x2+(56+26)x+60
Open the bracket in RHS of the equation
⇒ x2+76 x+60 = x2+56 x+26x+60
Take ‘x’ common from first two terms and 26
 common from last two terms in RHS
⇒ x2+76x+60=x(x+56)+26 (x+56)
Take (x+56)
 common and pair the remaining factors in RHS
⇒ x2+76x+60=(x+56)(x+26)
∴ Factorization of x2+76x+60  is (x+56)(x+26)
 
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