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Q.

Factorize Question Imageis ____


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Detailed Solution

Concept-Here you can also factor Question Image by rearranging it as ab2-a2b-ab+a2 or by rearranging it. ab2+a2-a2b-ab. Now consider the first two terms together, the last two terms together, find common factors, and factor them. Ultimately, you get the same coefficients a, Question Image,Question Image .
Get Question Image. Next, we need to factor the given equation. Factorization has been
found to be defined as decomposing or decomposing a polynomial into the product of the factors that produce the original polynomial.
First, let's think about Question Image. Think of the first two terms together and the last two terms together.  For the first two terms Question Imageand - Question Image, Question Image Question Imageis the greatest common divisor, so we can get Question Imageout. Then get the equation.
Question ImageNext, of the last two terms, Question Image and Question Image, Question Imageare common divisors. So that you can bring a Question Image to the outside, it looks like this:
Question ImageNow, the first term has Question Imageand  the second term has Question Image.
Question Image Therefore, you can take -1 outside Question Image. Therefore, it looks like this:
Question Image Now we can say that Question Imageis a common divisor of two terms. So, if you put Question Imageout, it looks like this:
Question Image Next, since a in Question Imageis a common divisor, we can get it out of a.  Now we will get the equation:
Question Image Hence, we can write it as:
Question Image Hence Question Imagehas the factors a, Question Imageand Question Image and we can write Question Imageas a product of these 3 factors.
Hence, the factors are a,(b-a)(b-1).
 
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