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Factorize: $3 xy + 2 x + 3 y + 2$

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$(x+2)(3y+3)$

$(x + 1) (3 y + 3)$

$(x + 1) (3 y + 2)$

$(x - 1) (3 y + 2)$

answer is B.

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Detailed Solution

The given expression: $3 xy + 2 x + 3 y + 2$

By Regrouping and taking out the common factors,

$3 xy + 3 y + 2 x + 2 = 3 y (x + 1) + 2 (x + 1)$

$= (x + 1) (3 y + 2)$

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