Factorize: ${\mathrm{x}}^3-2{\mathrm{x}}^2+2\mathrm{x}-4$

The given expression: ${\mathrm{x}}^{3 }- 2{\mathrm{x}}^2 + 2\mathrm{x} - 4$

By taking out the common factors, we get:

${\mathrm{x}}^3 - 2{\mathrm{x}}^{2 }+ 2\mathrm{x} - 4$

$= {\mathrm{x}}^2(\mathrm{x} - 2) + 2(\mathrm{x} - 2)$                       

$= ({\mathrm{x}}^{2 }+ 2)(\mathrm{x} - 2)$

The factors are $({\mathrm{x}}^2 + 2)(\mathrm{x} - 2)$.