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$F e^{2 +}$ is converted to $F e^{3 +}$ with $H_{2} O_{2}$ in presence of both acidic and basic medium. The ratio(simplest) between number of moles of $H_{2} O_{2}$ required to convert 1 mole of $F e^{2 +}$ to $F e^{3 +}$ in acidic and basic medium respectively is $x : y$ , then $(x + y)$ is:

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answer is 2.

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Detailed Solution

$H_{2} O_{2} + 2 H^{+} + 2 F e^{2 +} \to 2 F e^{3 +} + 2 H_{2} O H_{2} O_{2} + 2 F e^{2 +} \to 2 F e^{3 +} + 2 {(O H)}^{-}$

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