FeCl3 is added to excess NaOH forms

Fe(OH) 3 /H + ;Fe(OH) 3 /OH −

Fe(OH) 3 /H + ;Fe(OH) 3 /OH −

Fe(OH) 3 /Fe 3+ ;Fe(OH) 3 /OH −

Fe(OH) 3 /Fe 3+ ;Fe(OH) 3 /Na +

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FeCl₃ is added to excess NaOH forms

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FeCl₃/Fe³⁺;FeCl₃/OH⁻

Fe(OH)₃/H⁺;Fe(OH)₃/OH⁻

Fe(OH)₃/Fe³⁺;Fe(OH)₃/OH⁻

Fe(OH)₃/Fe³⁺;Fe(OH)₃/Na⁺

answer is B.

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FeCl₃+2NaOH⟶Fe(OH)₃+3NaCl

Fe(OH)₃exists on Fe₂O₃.xH₂O which adsorbs OH^-ions from NaOH present in excess to form Fe(OH)₃/Fe³⁺;Fe(OH)₃/OH⁻so it is a -ve colloid.

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