$Fe (CO)_{5} \overset{2 NO}{⟶} Fe (CO)_{2} (NO)_{2} + 3 CO$
Select the incorrect statement(s) regarding the above reaction.

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Hybridization state Iron is different in the reactant and product

Above reaction is not possible because two monodentate ligands replace three monodentate ligands

EAN of Fe remains the same

In this reaction NO acts as four electrons donating ligand

answer is A, D.

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Detailed Solution

$Fe (CO)_{5} \overset{2 NO}{⟶} Fe (CO)_{2} (NO)_{2}$

dsp³, trigonal bipyramidal sp³, tetrahedral

d⁸configuration zero d¹⁰configuration, zero unpaired e^-

unpaired electron O. No. of Fe = -2

O. No. of Fe = 0 O. No of N⁺= +1

NO is 3e^-donating in nature

$NO \to {NO}^{+} + e^{-}$

N⁺donate one e^-pair to Fe.

EAN $Fe (CO)_{5} = 26 + (5 \times 2) = 36$

$Fe (CO)_{2} (NO)_{2} = 26 + 2 + (2 \times 2) + (2 \times 2) = 36$

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