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$[Fe {(H_{2} O)}_{6}] {SO}_{4} \cdot H_{2} O \overset{Δ}{⟶} Residue (X) + Y ↑ + Z ↑$
Residue $(X)$ was treated with $HCl$ followed by $H_{2} S$ gas yielding yellowish white turbidity $(A)$ . When $(Y)$ is passed through $H_{2} S (aq .)$ , same yellowish white turbidity $(A)$ is obtained. Find the atomic mass of $(A)$ .

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answer is 32.

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Detailed Solution

${FeSO}_{4} \cdot 7 H_{2} OLi \to_{- 70_{2} C}^{300^{0} C} {FeSO}_{4}$

${FeSO}_{4} \to_{Strongly}^{∆} {Fe}_{2} O_{3} + {SO}_{2} + {SO}_{3}$

${Fe}_{2} O_{3} \overset{HCl / H_{2} S}{\to S ↓}$

${SO}_{2} \overset{H_{2} S}{\to (A)}$

So, the atomic mass of $(A)$ is 32.

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