${\mathrm{FeSO}}_4+\mathrm{KCN}\left(\text{ excess }\right)⟶$Complex X

Which of the following option is incorrect regarding complex X?

Since ${\mathrm{K}}_4\left[{\mathrm{E}}_{\mathcal{e}}(\mathrm{N}{)}_6\right]$ has no unpaired electron result in a low spin complex.

${\mathrm{FeSO}}_4+\mathrm{KCN}\text{ (excess) }\to {\mathrm{K}}_4\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]$

$\begin{array}{l}\mathrm{Fe}\left(26\right)\to \left[\mathrm{Ar}\right]3d^{6}4s^2\\ \mathrm{Fe}(+2)\to \left[\mathrm{Ar}\right]3d^{6}4s^{\circ }\end{array}$

Hence correct option is D.