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Q.

F_G and F_e represent gravitational and electrostatic force respectively between electrons situated at a distance of 10 cm. The ratio of F_G/F_e is of the order

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a

10⁴²

b

10

c

1

d

10^-42

answer is D.

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Detailed Solution

$F_{e} = (9 \times 10^{9}) [\frac{e \times e}{r^{2}}] and F_{G} = (6 .6 \times 10^{- 11}) [\frac{m_{e} \times m_{e}}{r^{2}}] ∴ \frac{F_{G}}{F_{e}} = \frac{6 \cdot 6 \times 10^{- 11}}{9 \times 10^{9}} \times \frac{{(m_{e})}^{2}}{(e)^{2}} = \frac{6 \cdot 6 \times 10^{- 11}}{9 \times 10^{9}} \times \frac{{(9 \cdot 1 \times 10^{- 31})}^{2}}{{(1 \cdot 6 \times 10^{- 19})}^{2}} = 10^{- 42}$

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