Fig. shows the P-V diagram of a cyclic process. If dQ is the heat energy supplied to the system, dU is the internal energy of the system and dW is the work
done by the system, then which of the following relations is/are correct

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dU= 0

dQ = -dW

dQ = dU - dW

dQ = dW

answer is C.

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Detailed Solution

In a cyclic process, the change in internal energy is zero because the system returns to its initial state. Thus dU = 0.
Now, according to the first law of thermodynamics $dQ = dU + dW$
or $dQ = dW (âµ dU = 0)$

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