Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2.0 cm2. The area of cross section at the outlet is 10 mm2. If the piston is pushed at a speed of 4cms-1, the speed of outgoing fluid is…………cms-1

From equation of continuityA1v1=A2v22cm2×4cm/sec=10mm2×v2v2=4cm/sec×210×10−2=80cm/sec

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Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2.0 cm². The area of cross section at the outlet is 10 mm². If the piston is pushed at a speed of 4cms^-1, the speed of outgoing fluid is…………cms^-1

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Detailed Solution

From equation of continuity
$\begin{array}{l} A_{1} v_{1} = A_{2} v_{2} \\ 2 {cm}^{2} \times 4 cm / \sec = 10 {mm}^{2} \times v_{2} \\ v_{2} = 4 cm / \sec \times \frac{2}{10 \times 10^{- 2}} = 80 cm / \sec \end{array}$

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