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Figure given below shows a beam of light converging at point P. When a concave lens of focal length 16 cm is introduced in the path of the beam at a place O shown by dotted line such that OP becomes the axis of the lens, the beam converges at a distance x from the lens. The value x will be equal to

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12 cm

36 cm

48 cm

24 cm

answer is D.

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Detailed Solution

By using lens formula

$\frac{1}{- 16} = \frac{1}{v} - \frac{1}{(+ 12)} \Rightarrow \frac{1}{v} = \frac{1}{12} - \frac{1}{16} = \frac{4 - 3}{48} \Rightarrow v = 48 cm$

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