Figure show the vertical section of a frictionless surface. A block of mass 2kg is  released from rest from position A; its KE as it reaches position C is $(g=10m{s}^{-2})$

Decrease in height is h = 14-7=7m

Total energy is conserved
Also KE at C = Loss in PE = mgh

substitute the given values m=2kg; g=10 m/square sec; h=7m

KE at C =2(10)7

KE at C= 140J