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Figure shows a boy on a horizontal platform A on a smooth horizontal surface, holding a rope attached to a box B. Boy pulls the rope with a constant force of 50 N. The combined mass of platform A and boy is 250 kg and that of box B is 500 kg. The velocity of A relative to the box B 5 s after the boy on A begins to pull the rope, will be :

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1 m/s

1.5 m/s

2 m/s

0.5 m/s

answer is B.

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Detailed Solution

$\large 50 = 250\,{a_A} \Rightarrow {a_A} = 0.2\,m/{s^2}$

$\large -50 = 500\,{a_B} \Rightarrow {a_B} = - 0.1\,m/{s^2}$

$\large {a_{AB}} = 0.3\,m/{s^2}$

$\large {V_{AB}} = {a_{AB}}\,t = 1.5\,m/s$

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