Figure shows a boy on a horizontal platform A on a smooth horizontal surface, holding a rope attached to a box B. Boy pulls the rope with a constant force of 50 N. The combined mass of platform A and boy is 250 kg and that of box B is 500 kg. The velocity of A relative to the box B 5 s after the boy on A begins to pull the rope, will be

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1 m/s

1.5 m/s

2 m/s

0.5 m/s

answer is B.

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Detailed Solution

$\begin{array}{l} 50 = 250 a_{A} \Rightarrow a_{A} = 0.2 m / s^{2} \\ 50 = 500 a_{B} \Rightarrow a_{B} = - 0.1 m / s^{2} \\ a_{AB} = 0.3 m / s^{2} \\ V_{AB} = a_{AB} t = 1.5 m / s \end{array}$

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