Figure shows a circuit used in an experiment to determined the emf and internal resistance of the battery C. A graph was plotted of the potential difference V between the terminals of the battery against the current I, which was varied by adjusting the rheostat. The graph is shown in fig (b); x and y are the intercepts of the graph with the axes as shown. What is the internal resistance of the battery?

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y/x

x/y

answer is D.

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Detailed Solution

As $V = ε - I r$

From graph it is clear that slope $= - r = - y / x$

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