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Figure shows a circular region of radius 𝑅 = √3𝑚 which has a uniform magnetic field B = 0.2T directed into the plane of figure. A particle having mass m=2g, speed 𝑣=0.3𝑚/𝑠 and charge q=1mC is projected along the radius of the circular region as shown in figure. Calculate the angular deviation produced in the path of the particle as it comes out of the magnetic field. Neglect any other force apart from the magnetic force (in degrees)

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answer is 60.

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Detailed Solution

The circle in which particle rotates will be perpendicular to the given circle and has a radius 3. Forming a triangle with the two radii and the line joining centers, we get the angle of deviation to be 60 deg.

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